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	<title>And Slaters Go Plop &#187; birthday</title>
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		<title>The Chances of Sharing a Birthday</title>
		<link>http://damian.peterson.net.nz/2008/05/27/the-chances-of-sharing-a-birthday/</link>
		<comments>http://damian.peterson.net.nz/2008/05/27/the-chances-of-sharing-a-birthday/#comments</comments>
		<pubDate>Mon, 26 May 2008 20:00:48 +0000</pubDate>
		<dc:creator>Damian</dc:creator>
				<category><![CDATA[Entertainment]]></category>
		<category><![CDATA[birthday]]></category>
		<category><![CDATA[probability]]></category>
		<category><![CDATA[puzzle]]></category>

		<guid isPermaLink="false">http://damian.peterson.net.nz/?p=144</guid>
		<description><![CDATA[In any given group of people, how many people do you think there need to be in order for there to be a 50% chance of at least two people sharing the same birthday? 365 / 2 = ~183 people? Nope. Think again. This is not a trick question, just plain old mathematical probability. The [...]]]></description>
			<content:encoded><![CDATA[<p>In any given group of people, how many people do you think there need to be in order for there to be a 50% chance of at least two people sharing the same birthday?</p>
<p>365 / 2 = ~183 people?</p>
<p>Nope. Think again. This is not a trick question, just plain old mathematical probability.</p>
<p>The answer, which I found very counter-intuitive at first, is 23. It&#8217;s called the <a href="http://en.wikipedia.org/wiki/Birthday_paradox">Birthday Paradox</a>. The mistake I was making (and that most people would probably make) is that I was picking a single birthday and thinking of the probability of any given birthday matching it rather than moving on and testing for every other birthday possibility in the group.</p>
<p>I still struggle with it however, when I think back to school days where there should have been a 100% chance of two kids sharing a birthday in any two classes. I can&#8217;t remember anyone sharing a birthday at all.</p>
<p>(Or have I done the math wrong here by assuming that two classes of 23 students will give a 100% chance? Perhaps this equates to 75% instead or remains at 50%? Gaaah! I <em>knew</em> I should have listened in school!).</p>
<p>Jack, if you are reading this perhaps you could test this to see if it really works in a class situation?</p>
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